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4 years ago ::
Mar 10, 2009 - 4:59PM
#31
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Date Joined:
Jul 11, 2008
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The problem with many Timmies, is that their ability to have fun is largely decided on what they can get everyone else around them to play. So they will get really upset when their spell gets countered, or their creature destroyed, or they encounter mass removal, and so on. It's a really annoying personality type to deal with sometimes.
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4 years ago ::
Mar 10, 2009 - 5:11PM
#32
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Date Joined:
Oct 23, 2006
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That's more of a scrub mentality than a Timmy, I would say. I play with a number of people that consider themselves Timmies that actually understand and appreciate interaction. Sure they are happier when they get to do their thing, but they understand that you need an opponent to play and he is not always going to let you just cast everything or keep it on the board.
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4 years ago ::
Mar 10, 2009 - 5:51PM
#33
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Date Joined:
Aug 12, 2008
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I opened a progenitus  at the pre-release and I had to play it. I laughed hard outloud at this. As I was this guy to a tee. I had one and I had to run it. When did I become a timmy? lol. There are much worse things out there lol.
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4 years ago ::
Mar 10, 2009 - 6:19PM
#34
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Date Joined:
Mar 25, 2005
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(I've done something similar. An Enduring Ideal  deck of mine has my all-time favourite combo in it, which I fetched out over the course of 3 turns: Doubling Season  , Opalescence  , and Followed Footsteps  on the Season. I got up to 1031 Seasons in play by the time I won attacking with 11 5/5s. Next turn I would have got over a googol of Seasons. :D )
You definitely need some Paradox Haze  s in that deck so that you have a chance to get 2^1031 tokens before you attack for lethal.
If you also throw in a Copy Enchantment  , copying nothing, with an extra Followed Footsteps on it, then you can make token copies of Paradox Haze every upkeep, and the number of tokens quickly becomes much larger than anything that can be described in terms of any commonly used notation for describing numbers. (If you start with one Season and one Haze, next turn you will have 3 Seasons and 9 Hazes during the first upkeep, and 11 Seasons and 2057 Hazes during the second. The turn after, the number of Seasons will be approximately 2^2^...2^11, where the number of "2^"s is 2057 and the association is right to left. This is a huge, huge number, and you can make it even bigger by using some of the Copy Enchantment copies to copy Footsteps or extra Doubling Seasons.)
This begs the question of what happens if your opponent has an "infinite" life combo, and wants to gain enough life to survive 1000 turns of attacks from animated Doubling Season s. Clearly the amount of damage you can do is finite, so your opponent can choose a life total large enough, but does he/she actually have to be able to describe said life total in numerical terms?
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4 years ago ::
Mar 10, 2009 - 6:28PM
#35
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Date Joined:
Jun 14, 2006
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This begs the question of what happens if your opponent has an "infinite" life combo, and wants to gain enough life to survive 1000 turns of attacks from animated Doubling Season s. Clearly the amount of damage you can do is finite, so your opponent can choose a life total large enough, but does he/she actually have to be able to describe said life total in numerical terms?
You could try factorials. Last time I had an infinite loop I went with 10^(10^100)! iterations of it. Then you could maybe go with 10^(2^(10^(10^100)!))! if you need to get bigger. I don't know about exact values, but if you stack enough exponents together and toss in some exclamation points, it's really easy to get arbitrarily huge numbers.
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4 years ago ::
Mar 10, 2009 - 6:38PM
#36
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Date Joined:
Feb 25, 2009
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Hmm. I'm actually wondering if Graham's number is big enough to work here XD. I gain something like... 10-->10-->10-->2-->4-->56-->67-->45-->67-->2-->42-->3 =P
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4 years ago ::
Mar 10, 2009 - 7:25PM
#37
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Date Joined:
Aug 31, 2005
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Man. They really ruined the Forsythe story by tossing in pictures from the three-color block.
Poor editorial choice on the part of whoever made that (still pretty good) picture.
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4 years ago ::
Mar 10, 2009 - 10:11PM
#38
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Date Joined:
Mar 25, 2005
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You could try factorials. Last time I had an infinite loop I went with 10^(10^100)! iterations of it. Then you could maybe go with 10^(2^(10^(10^100)!))! if you need to get bigger. I don't know about exact values, but if you stack enough exponents together and toss in some exclamation points, it's really easy to get arbitrarily huge numbers.
X! grows faster than 2^X, but not as fast as 2^(2^X). Hence, you'd need hundreds of exponentials and factorials to get the number of copies of Doubling Season that you'd have after 2 turns, let alone 100.
Hmm. I'm actually wondering if Graham's number is big enough to work here XD.
I gain something like... 10-->10-->10-->2-->4-->56-->67-->45-->67-->2-->42-->3 =P
This, on the other hand, would probably work.
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4 years ago ::
Mar 11, 2009 - 3:23AM
#39
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The problem with many Timmies, is that their ability to have fun is largely decided on what they can get everyone else around them to play. So they will get really upset when their spell gets countered, or their creature destroyed, or they encounter mass removal, and so on. It's a really annoying personality type to deal with sometimes.
Nooooo counterspells and mass removal, -that's- annoying to play against sometimes 
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4 years ago ::
Mar 11, 2009 - 3:49AM
#40
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Date Joined:
Mar 16, 2004
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Hee, yay, it's the "how huge can your numbers go" question. ToothyWiki's page MagicTheGathering/ComboMeThis has a discussion of that (inspired by this old thread from before the boards moved - find UyOwned's post). What's the greatest amount of mana you can make by turn 6, with just the 13 cards you've drawn by that point, and with no infinite combo?
Recall that a^^b = a^(a^(...a tower b high...(a^a)...)). So 2^^3 = 2^2^2 = 2^4 = 16; and 3^^2 = 3^3 = 27; and 3^^3 = 3^(3^3) = 3^27 = 7,625,597,484,987.
This notation can be extended to a^^^b = a^^(a^^(...a tower b high...(a^^a)...)). It can be extended even further, but this'll do for now.
2 ^^^ 2 is 2^^2 = 2^2 = 4.
2 ^^^ 3 is 2^^4 = 2^^4 = 2^2^2^2 = 65536
2 ^^^ 4 is 2^^65536 = 2^2^2^(...65536 levels...)^2^2.
And remember, the top 4 levels of this tower make 65536. The 5th level down is 2^65536, which has nearly 20000 digits. There are another 65531 levels to go. This 2^^^4 is one absurd, unimaginably large number.)
2 ^^^ 5 is 2^^ that number, which is a tower that high of 2s.
2 ^^^ 13 is how many creatures this guy makes on turn 6, using only 13 cards.
This is probably going a bit beyond "Timmy" and into "Maths geek", though... 
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