All players win simultaneously

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What if in a two-player game both players would win simultaneously? The rules does not cover that case!
They only say that:
104.4a If all the players remaining in a game lose simultaneously, the game is a draw.

No rule says:
"If all the players remaining in a game win simultaneously, the game is a draw."

Of course in multiplayer we have:
104.3h In a multiplayer game, an effect that states that a player wins the game instead causes all of
that player’s opponents to lose the game.

So, "all players win" becomes "all players lose" and 104.4a applies.

What about two-player game?
You're rule-picking. If all players win, it's a draw.

It's interesting that the rules don't cover it. Maybe make thread in RT&T?

Rules Advisor

Please autocard: [c]Shard Phoenix[/c] = Shard Phoenix.

If all players win, it's a draw.

That is what logic and common sense say... but not rules. I don't know if it is even possible to generate such situation. It's easier to lose than to win.
each player has an empty library, controls Laboratory Maniac and Jace Beleren +2
proud member of the 2011 community team
So... if there is no "If all the players remaining in a game win simultaneously, the game is a draw" rule does it mean than both players win and nobody loses?
no, it's a draw
it might not be in the rules as such, but it is a draw

as has been said, make a thread in RT&T to ask if this hole can be closed
proud member of the 2011 community team
OK
each player has an empty library, controls Laboratory Maniac and Jace Beleren +2


Even this doesn't work. The active player would win.

Rule 120.2a
If an effect instructs more than one player to draw cards, the active player performs all of his
or her draws first, then each other player in turn order does the same.
Rules Advisor
So, there actually is no way to make everybody win simultaneously?

If I steal a hundred dollar from a loot of one thousand, people might notice;

If I steal a hundred dollar from a loot of one million, I might get away with it;

If I wish to steal even more and still go unnoticed, I need to make the loot bigger.

 

Now you know why taxes always go up.

 

Looting: ''the plundering of public assets by corrupt or greedy authorities'' (Wikipedia)

So, there actually is no way to make everybody win simultaneously?

None that i know of. 
All players Control Darksteel Reactor with 20 charge counters and Abyssal Persecutor.

Detention Sphere On Persecutor.


???
that's a triggered ability
those go onto the stack in APNAP order

so the least active player wins ;)
proud member of the 2011 community team
Ways to win a two-player game that can't result in two players winning:


  • Rule 104.2a: Be the last one not to have lost.

  • Triggered or activated abilities with an effect that causes a player to win the game in the effect.

  • Laboratory Maniac (because of 120.2a).


Ways to win a two-player game that can result in two players winning:


So when the reactors trigger the first time and Persicutor stops the win would it even trigger again when Percy leaves? Is it triggering constantly?
So when the reactors trigger the first time and Persicutor stops the win would it even trigger again when Percy leaves? Is it triggering constantly?


It will trigger, and when the ability resolves, it will trigger again.  (and again, etc)


 
If the Abyssal Persecutor weren't exiled the game would have ended in a draw due to a non-optional infinite loop.
each player has an empty library, controls Laboratory Maniac and Jace Beleren +2


Even this doesn't work. The active player would win.

Rule 120.2a
If an effect instructs more than one player to draw cards, the active player performs all of his
or her draws first, then each other player in turn order does the same.



But would not all the draws have to happen before someone would lose/win?
Laboratory Maniac has a replacement that doesn't wait for state-based actions. You win on the spot at the moment you would draw the card, even if it's during the resolution of something else.
Rules Advisor
each player has an empty library, controls Laboratory Maniac and Jace Beleren +2


Even this doesn't work. The active player would win.

Rule 120.2a
If an effect instructs more than one player to draw cards, the active player performs all of his
or her draws first, then each other player in turn order does the same.

But would not all the draws have to happen before someone would lose/win?

without the Maniac all players would lose, since that is checked as a SBA

but the Maniac has a replacement effect that kicks in the moment you draw
I overlooked that so I came to the wrong scenario
proud member of the 2011 community team
So, there actually is no way to make everybody win simultaneously?


"At the beginning of the next upkeep, each player wins the game."

What would THAT mean, that everyone wins or that everyone loses ? :P

Rules Advisor

The Basic rulebook, read it! A lot of basic questions are answered there!

How to autocard :
Type [c]Black Lotus[/c] to get Black Lotus.
Type [c=Black Lotus]The Overpowered One[/c] to get The Overpowered One.

As mentioned, that results in a draw in a multiplayer game and both players winning in a two-player game. Chaikov was asking if it's even possible to encounter that situation in a two-player game. It's only possible with an Un- card.